Question

paranteză rotundă 6 plus 2 la puterea 10 :2^8)^7:10^5-9×10

Answer 1

(6+[tex] 2^{10} [/tex]:$2^{8}$$)^{7}$:$10^{5}$-90

=(6+$2^{2}$$)^{7}$:$10^{5}$-90

=[tex] 10^{7} [/tex]:$10^{5}$-90

=$10^{2}$-90

=100-90

=10.