Question

poate cineva sa facă aceste doua ex pana la 10?
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Answer 1

1.

 = 90° => ABC = dreptunghic

$=> {BC}^{2} = {AB}^{2} + {AC}^{2}$

${BC}^{2} = {15}^{2} + {20}^{2} = 225 + 400 = 625$

$BC = \sqrt{625} = 25cm$

$P_{ABC} = 15 + 20 + 25 = 60cm$

AS - înălțime

$= > AS = \frac{AB \times AC}{BC} = \frac{15 \times 20}{25} = \frac{300}{25} = 12cm$

$AM = \frac{BC}{2} = \frac{25}{2} = 12.5cm$

2.

 = 90° => ABC = dreptunghic

$=> {BC}^{2} = {AB}^{2} + {AC}^{2}$

${AB}^{2} = {BC}^{2} - {AC}^{2}$

$= {30}^{2} - {18}^{2} = 900 - 324 = 576$

$AB = \sqrt{576} = 24cm$

$P_{ABC} = 24 + 18 + 30 = 72cm$

AS - înălțime

$= > AS = \frac{AB \times AC}{BC} = \frac{24 \times 18}{30} = \frac{432}{30} = 14.4cm$

$AM = \frac{BC}{2} = \frac{30}{2} = 15cm$