Question

Poate cineva, va rog, sa-mi spuna doar cum sa fac cea din paranteza daca l-am transformat pe 0,(3) in 3 pe 9? Va rog repede

Answer 1

$\bf 1\dfrac{3}{10} -\Big(0,(3)+\dfrac{5}{6}\Big)=$

$\bf \dfrac{1\cdot10+3}{10} -\Big(\dfrac{3}{9}+\dfrac{5}{6}\Big)=$

$\bf \dfrac{13}{10} -\Big(\dfrac{\not3}{\not9}+\dfrac{5}{6}\Big)=$

$\bf \dfrac{13}{10} -\Big(\dfrac{1}{3}+\dfrac{5}{6}\Big)=$

$\bf \dfrac{13}{10} -\Big(\dfrac{1\cdot2}{3\cdot2}+\dfrac{5}{6}\Big)=$

$\bf \dfrac{13}{10} -\dfrac{2+5}{6}=$

$\bf \dfrac{13}{10} -\dfrac{7}{6}=$

$\bf \dfrac{13\cdot6}{10\cdot6} -\dfrac{7\cdot10}{6\cdot10}=$

$\bf \dfrac{78-70}{60}=$

$\bf \dfrac{8}{60}=$

$\bf \dfrac{\not8}{\not60}=$

$\boxed{\bf \dfrac{2}{15}}$