Question

Problema 1 : ms =500g' c=9% calculati masa apei ...mie mi a dat 455g
Problema 2: md1=10g,c1=2%,md2=20g,c2=4%. Aflati md final si conentratia finala.
Plsssss maine ne pune note

Answer 1

Problema 1 :
c=md/ms×100
md=c×ms/100=9×500/100=9×5=45 g
m apa=ms-md=500-45g=455g
Problema 2 :
mdf=10+20g=30g
c1=md1/ms1×100
ms1=md1/c1×100
ms1=10/2×100=5×100=500g
c2=md2/ms2×100
ms2=md2/c2×10=20/4×10=5×10=50g
msf=500+50=550 g
cf=mdf/msf×100=30/550×100=3000/550=5,454 g