Question

Punctul 1 ,subpunctele f),g),h),i)
Dau coroană

Answer 1

f) (4+ 2^192:2^188) :5 = (4+2^4):5 = (4+16):5 = 20:5 = 4

g) (1+2*2^2*2^4):(2^7+1) = (1+2^7):(1+2^7) = 1

h) [(3^3)^12 : 3^2^5 - 56)]:5 = (3^36:3^32 - 56):5 = (3^4-56):5 = (81-56):5 =25:5 = 5

i) 8^16 : (2*2^4*2^10)^3 - 2^1 - 2^0 = (2^3)^16 : (2^15)^3 - 2 - 1 = 2^48: 2^45 - 2 -1 = 2^3 - 2 - 1 = 8 - 2 - 1 = 5