Question

R=3 abc este de 3/2 iar BC=2 sa e calculeze sinA

Answer 1

Teorema sinusurilor este $\frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC}=2R,deci, \frac{BC}{sinA}= \frac{2}{sinA}=2*3,sau,sinA= \frac{1}{3}$