Question

Rapid va rog eu ……..

Answer 1

$\it a=\Big(\dfrac{^{6)}1}{\ 2}+\dfrac{^{4)}1}{\ 3}-\dfrac{1}{12}\Big)\cdot\sqrt{7\dfrac{1}{9}}=\dfrac{\ 9^{(3}}{12}\cdot\sqrt{\dfrac{64}{9}}=\dfrac{3}{4}\cdot\dfrac{8}{3}=\dfrac{24}{12}=2\\ \\ \\ b=\Big(\dfrac{^{6)}1}{\ 2}-\dfrac{^{4)}1}{\ 3}+\dfrac{1}{12}\Big)\cdot\sqrt{5^2-3^2}=\dfrac{\ 3^{(3}}{12}\cdot\sqrt{16}=\dfrac{1}{4}\cdot4=1\\ \\ \\ m_g=\sqrt{a\cdot b}=\sqrt{2\cdot1}=\sqrt2$