Question

rationalizati nimotorul raportului √3/√3-√2

Answer 1

$\frac{\sqrt3}{\sqrt3-\sqrt2}=\frac{\sqrt3(\sqrt3+\sqrt2)}{(\sqrt3-\sqrt2)(\sqrt3+\sqrt2)}=\frac{3-\sqrt6}{\sqrt3^2-\sqrt2^2}=\frac{3-\sqrt6}{3-2}=3-\sqrt6$