Question

rezolva ecuația de gradul 2 . descompune:
a)x²-6x+9
b)x²-10x+25
c)x²-8x+16
d)4x²-4x+1
​

Answer 1

Răspuns:

$a) \: {x}^{2} - 6 x + 9 = 0 \\ a = 1 \\ b = - 6 \\ c = 9 \\ \Delta = {b}^{2} - 4ac = ( - 6) {}^{2} - 4 \times 1 \times 9 = 36 - 36 = 0$

$b) \: {x}^{2} - 10x + 25 = 0 \\ a = 1\\ b = - 10 \\ c = 25 \\ \Delta = {b}^{2} - 4ac = ( - 10) {}^{2} - 4 \times 1 \times 25 = 100 - 100 = 0$

$c) \: {x}^{2} - 8x + 16 = 0 \\ a = 1 \\ b = - 8 \\ c = 16 \\ \Delta = b {}^{2} - 4ac = ( - 8) {}^{2} - 4 \times 1 \times 16 = 64 - 64 = 0$

$d) \: 4x {}^{2} - 4x + 1 = 0 \\ a = 4\\ b = - 4\\ c = 1 \\ \Delta = {b}^{2} - 4ac = ( - 4) {}^{2} - 4 \times 4 \times 1 = 16 - 16 = 0$

Formule:

$\bf\red{ \boxed{ax {}^{2} + bx + c = 0}}$

$\bf \red{ \boxed{\Delta = {b}^{2} - 4ac}}$