Question

rezolva ecuatiile : a) x+1/5=3/5 b)9/2+x=15/2c) x+5/7=4/3

Answer 1

a)x+1/5=3/5
=>x=3/5-1/5
x=2/5

b)9/2+x=15/2
=>x=15/2-9/2
x=6/2(poti simplifica cu 2)
=>x=3

c)x+5/7=4/3
Aducem la acelasi numitor
=>5/7 il amplificam cu 3
si pe 4/3 il amplificam cu 7
=>5/7=15/21
si4/3=28/21
=>x+15/21=28/21
x=28/21-15/21
x=13/21

Answer 2

a) x+1/5=3/5
x=3/5-1/5
x=3-1totul supra/5
x=2/5

b) 9/2+x=15/2
x=15/2-9/2
x=15-9 totul supra /2
x=6/2
simplificat fractia 6/2 cu 2 =3/1=3
x=3

c) x+5/7=4/3
x=4/3-5/7
x=7×4 -3×5totul supra /21
x=28-15 totul supra /21
x=13/21