Question

rezolva in multimea nr intregi ecuatia: (3-6/5)^2:9/5-0,2=x/10

Answer 1

[tex](3-1,2)^2:\frac{9}{5}-0,2=\frac{x}{10}\\ 1,8^2:1,8-0,2=\frac{x}{10}\\ 1,8-0,2=\frac{x}{10}\\ 1,6=\frac{x}{10}\\ x=1,6\cdot 10\\ x=16[/tex]

Answer 2

(9/5)²  ; (9/5) -0,2=x/10

x/10=9/5-0,2
x=(9/5) *10 -0,2*10
x=9*2-2
x=8*2
x=16


Verificare
9/5-0,2=1,6
1,8-0,2=1,6
adevarat ;binerezolvat