Question

rezolvati ecuatile a) 2(2x+7)+3(x-1)=6(x-3)+18 b) 2x+3(3x-1)=8(1-7x)+2+3x

Answer 1

a) 2(2x+7)+3(x-1)= 6(x-3) + 18 ⇔

⇔ 4x+14+3x-3= 6x-18+18

⇔ 7x+11= 6x

⇔ 7x-6x= -11

⇔ x= -11

v: x= -11

2[2*(-11)+7] + 3(-11-1) = 6(-11-3) +18 ⇔

⇔2(-22+7)+3*(-12)= 6*(-14)+18

⇔ 2*(-15)+3*(-12)= 6*(-14)+18

⇔-30-36= -84+18

⇔ -66=-66 (A) ⇒ S={-11}

b) 2x+3(3x-1)= 8(1-7x)+2+3x ⇔

⇔ 2x+9x-3= 8-56x+2+3x

⇔11x-3= -53x+10

⇔64x= 13

⇔ x= $\frac{13}{64}$ ⇒ S= {$\frac{13}{64}$ }