Question

Rezolvati ecuatua :a) (x+2)la 2 = 16
b) |x-3| = 6
2. Descompuneti : 
a) 3x la 3 + 6x la 2 + 3x
b) ( x+1) la 2 - 9Iti multumesc mult pentru ca ma ajutii :* ♥ ♥ ♥

Answer 1

1)
a) (x + 2)² = 16
x + 2 = ±√16
x1 = 4 - 2 = 2
x2 = -4 - 2 = -6

b) |x-3| = 6
x - 3 = ± 6
x1 = 6 + 3 = 9
x2 = -6 + 3 = -3

2)
a) 3x³ + 6x² + 3x = 3x(x² + 2x + 1) = 3x(x+1)² = 3 * x * (x + 1) * (x + 1)
b) (x + 1)² - 9 = (x + 1 - 3)(x + 1 +3) = (x - 2)(x + 4)