Question

Rezolvați în R ecuația
1)1/2 (1-5x)+4 (x^2-4)-3/4=5/8 (2-x)+4x^2-3x
2)2x^3-x+3=5 (x+2/5x^3-2)-4x
3)3x (x^2-x+1)-4x=5x^2+2 (1-x^2)+3x^3-X
4)(4x-1)(4x+1)-5x=-4 (x-4x^2)-7 (x+3)

Answer 1

1) .1/2(1-5x)+4(x²-4)-3/4=5/8(2-x)+4x²-3x
Inmultim cu 8 expresia
4(1-5x)+32(x²-4)-6=5(2-x)+32x²-24x
4-20x+32x²-128-6=10-5x+32x²-24x
aducem toti termenii in partea stanga
4-20x+32x²-128-6-10+5x-32x²+24x=0
9x -140=0, x=140/9

2). 2x³-x+3=5(x+2/5 x³-2)-4x
 2x³-x+3=5x+2x³-10-4x
2x-13=0, x=13/2