Question

Rezolvati in z ecuatiile:a) 2x+radical din 25=radical din 49;.b)radical din 100-3x=radical din 16-6;c)4(x+radical din 4)=-radical din 16;d)radical din 121 -x=radical din 144;e)2radical din x=-6;f)radical din x:(-3)=-4;

Answer 1

$a).2x+ \sqrt{25} = \sqrt{49} \\ 2x+5=7 \\ 2x=7-5 \\ 2x=2 \\ x= \frac{2}{2} \\ x=1 \\ b). \sqrt{100} -3x= \sqrt{16} -6 \\ 10-3x=4-6 \\ -3x=4-6-10 \\ -3x=-12 \\ x= \frac{-12}{-3} \\ x=4$
$c).4(x+ \sqrt{4} )=- \sqrt{144} \\ 4(x+2)=-12 \\ 4x+8=-12 \\ 4x=-12-8 \\ 4x=-20 \\ x=- \frac{20}{4} \\ x=-5 \\ d). \sqrt{121} -x= \sqrt{144} \\ 11-x=12 \\ -x=12-11 \\ -x=1 \\ x=-1$
$e).2 \sqrt{x} =-6 \\ (2 \sqrt{x} )^2=(-6)^2 \\ 4x=36 \\ x= \frac{36}{4} \\ x=9$
$f). \sqrt{x} :(-3)=-4 \\ \sqrt{x} =-4*(-3) \\ \sqrt{x} =12 \\ ( \sqrt{x} )^2=12^2 \\ x=144$