Question

rezolvati problema
1. Se dizolva 200 g de solutie NaOH de conc. 80% cu 600 g solutie de NaOh de conc.=40%. Aflati concentratia finala.

Answer 1

se da:
m sol1=200g
W(omega)1=80%
m sol2=600g
W2=40%
_______________
W=?
                                     rezolvare

m sub1=(msol1*w)/100%⇒msub1=(200g*80%)/100%⇒msub1=160g;
msub2=(600g*40%)/100%⇒msub2=240%
msol=msol1+msol2⇒msol=200g+600g⇒msol=800g;
msub=msub1+msub2⇒msub=160g+240g⇒msub=400g
W=(msub/msol)*100%⇒W=(400g/800g)*100%⇒W=50%;
Rs:W=50%