Question

rezolvati urmatoarele,sa se afle necunoscutele: (2xa+3)x(2xa+4)=56

Answer 1

(2xa+3)x(2xa+4)=56,iar x =4 (6a)+(8a)=56==»x =4

Answer 2

 [tex]Daca\,(2\cdot{a}+3)(2\cdot{a}+4)=56\,\,\\ \Rightarrow2a+3=7\,si\,2a+4=8\,\\fiind \,produsul\,a\,doua\,nr.consecutive\,!\\ inseamna\,ca\,a=(7-3):2=2\,\,\,si\\.\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,a=(8-4):2=2\,.\\ deci\,\,\fbox{a=2} [/tex]