Question

sa se afle x, y, z daca sunt invers proportionale cu 2, 3, 4, iar suma lor este13

Answer 1

x/(1/2)=k  x=k/2
y/(1/3)=k  y=k/3
z/(1/4)=k  z=k/4
x+y+z=13
k/2+k/3+k/4=13
6k+4k+3k=156
13k=156
k=12
x=k/2=12/2=6
y=k/3=12/3=4
z=k/4=12/4=3