Question

Sa se calculeze masa de substanta si masa clorurii de sodiu, care s-a folosit la obtinerea a 5,6 l de clorura de hidrogen .

Answer 1

Varianta liceu
x moli..............5,6 litri
2NaCl+H2->2HCl+2Na
2......................2×22,4
x=(5,6×2)/(2×22,4)=0,25 moli NaCl
MNaCl=ANa+ACl=23+35,5=58,5 g/mol
n=m/M=>m=n×M=0,25×58,5=14,625 g NaCl

Varianta clasele 7-8
x moli..............5,6 litri
2NaCl+H2->2HCl+2Na
2......................2×22,4
x=(5,6×2)/(2×22,4)=0,25 moli NaCl
y g..................5,6 litri
2NaCl+H2->2HCl+2Na
2×58,5..........2×22,4
MNaCl=ANa+ACl=23+35,5=58,5 g/mol
y=(2×58,5×5,6)/(2×22,4)=14,625 g NaCl