Question

Sa se calculeze
$\sqrt[3]{24} - 3 \sqrt[3]{192} + \sqrt[3]{-81}$

Answer 1

$\sqrt[3]{24} - 3\sqrt[3]{192} + \sqrt[3]{-81} =$
$\sqrt[3]{24} = 2\sqrt[3]{3}$
$3\sqrt[3]{192} = 12\sqrt[3]{3}$
$\sqrt[3]{-81} =- 3\sqrt[3]{3}$
$2\sqrt[3]{3} -12 \sqrt[3]{3} - 3\sqrt[3]{3} =<strong>-13 \sqrt[3]{3}$