Question

sa se determine parametrul real m din ecuatia (cu radacinile x1 si x2):
x^2+(1-m)x+m=0, stiind ca x1^2+x2^2=6
va rog muuuuult!!!

Answer 1

x1^2+x2^2=6

(x1+x2)^2 -2x1x2=6

x1+x2=m-1
x1x2=m

(m-1)^2 -2m-6=0
m^2 -2m+1 -2m -6=0
m^2 -4m-5=0
(m+1)(m-5)=0

m1=-1
m2=5