Question

Salut, ma poate ajuta cineva cu rezolvarile la exercitiile de mai jos ? Cu tot cu rezolvare, nu doar raspunsul direct. Multumesc ! :)

Answer 1

2)1-1/4:0,25=1-4/4=4/4-4/4=0
3)(1/2-1/5)*10/3=(5/10-2/12)*10/3=3/10*10/3=1
4)1/2:0,5-1=2/2-1=2/2-2/2=0
5)(√5+2)la patrat-4√5=8,4721-8,9442=-0,4721

Answer 2

$\displaystyle 1)\left(1- \frac{1}{2} \right)\left(1- \frac{1}{3} \right)\left(1- \frac{1}{4} \right)= \frac{2-1}{2} \cdot \frac{3-1}{3} \cdot \frac{4-1}{4} = \\ \\ = \frac{1}{2} \cdot \frac{2}{3} \cdot \frac{3}{4} = \frac{1}{4} \\ \\ 2)1- \frac{1}{4} :0,25=1- \frac{1}{4} : \frac{25}{100} =1- \frac{1}{4} : \frac{1}{4} =1- \frac{1}{4} \cdot 4=1-1=0\\ \\ 3)\left( \frac{1}{2} - \frac{1}{5} \right)\cdot \frac{10}{3} = \frac{5-2}{10} \cdot \frac{10}{3} = \frac{3}{10} \cdot \frac{10}{3} =1$
$\displaystyle 4) \frac{1}{2} :0,5-1= \frac{1}{2} : \frac{5}{10} -1= \frac{1}{2} : \frac{1}{2} -1= \frac{1}{2} \cdot 2-1=1-1=0 \\ \\ 5)\left( \sqrt{5} +2 \right)^2-4 \sqrt{5} =\left( \sqrt{5} \right)^2+2 \cdot \sqrt{5} \cdot 2+2^2-4 \sqrt{5} = \\ \\ =5+4 \sqrt{5} +4-4 \sqrt{5} =9$