Question

Scrieti prin ecuatie problema:suma a 3 nr. consecutive este 215. Aflati nr.!

Answer 1

x + (x+1) + (x+2)=215

3x+3=215

3x=212

x= 212/3

x+1= 212/3+1=215/3

x+2=212/3+2=218/3

Answer 2

a+a+1+a+2+a+3= 4a+6=215 3a=209=>a=209÷3=69,69 SPER VĂ TE-AM AJUTAT