Question

se considera expresie E(x)=($\frac{1}{x-2}- \frac{x}{ x^{2} -4}$)·$\frac{2}{(x-2)(x+2)}$ x estenr real x$\neq$-2 x$\neq$2.Aratati ca E(x)=1 pt ori ce nr real x,x$\neq$-2 se x$\neq$2.
Va rog ajutatima ca nu stiu cum se rezolva..........

Answer 1

E(x)=1/(x-2)-x/(x^2-4):2/(x-2)(x+2)=(x+2-x)/(x^2-4):2/(x-2)(x+2)=2/(x-2)(x+2)*(x-2)(x+2)/2 =1