Question

se considera functia f:R->R, f(x) =2x+1.Sa se det f(-2)+f(-1)+f(0)+f(1)​

Answer 1

f(x) = 2x + 1

f(-2) + f(-1) + f(0) + f(1) = ?

f(-2) = 2 * (-2) + 1

f(-2) = - 4 + 1

f(-2) = - 3

f(-1) = 2 * (-1) + 1

f(-1) = - 2 + 1

f(-1) = - 1

f(0) = 2 * 0 + 1

f(0) = 0 + 1

f(0) = 1

f(1) = 2 * 1 + 1

f(1) = 2 + 1

f(1) = 3

  - 3 + (-1) + 1 + 3 =

= - 3 - 1 + 1 + 3 =

= - 4 + 1 + 3 =

= - 3 + 3 =

= 0

 * Sper că te-am ajutat! *