Question

Se da numarul a= 2∧1990-2∧1989-2∧1988. Aflati x din proportia a supra x = 4^993 supra 0,25

Answer 1

a=2^1988(2^2-2^1-1)
a = 2^1988(4-2-1)
a = 2^1988*1
a = 2^1988
a/x = (2^2)^993/0,25
2^1988/x = 2^1986/0,25
x = $\frac{ 2^{1988} * 0,25 }{ 2^{1986} }$

x = 2^2 * 0,25
x = 4*0,25
x = 1