Question

Se stie ca a=11 si b+c=8.Calculati:
b) 2a+3b+3c
Ajutati-ma!!!!!!!!!!!!!!!

Answer 1

$a=11 \\ b+c=8 \\ 2a+3b+3c=2a+3(b+c)=2 \cdot 11+3 \cdot 8=22+24=46 \\ \boxed{2a+3b+3c=46}$

Answer 2

2a+3b+3c=2·11+3(b+c)=22+3·8=22+24=46