Question

simplificati fractia 26^75-2^71 supra 2^74+2^72

Answer 1

$\frac{26^{75}-2^{71} }{2^{74}+2^{72}}= \frac{ (2\cdot 13)^{75}-2^{71} }{ 2^{71}\cdot(2^{3} +2)} } = \frac{ 2^{75}\cdot13 ^{75}-2^{71} }{2^{71}\cdot(2^{3} +2)} = \frac{ 2^{71}\cdot (2^{4}\cdot 13^{75} -1)}{2^{71}\cdot(2^{3} +2)} = \frac{2^{4}\cdot 13^{75} -1}{2^3+2}$