Question

Simplificati raportul : $\frac{2 x^{2} -7x+3}{ x^{2} -9}$ prin x-3 , unde x este numar real , $x \neq -3 ; x \neq 3.$

Answer 1

a=2
b= -7
c=3
Δ= 49- 24= 25

x1;x2= (7+ /- √25)/2*2= (7 + /- 5)/4
x1= (7+5)/4= 12/4=3
x2=(7-5)/4=2/4=1/2

2x²-7x+3= 2*(x-1/2)(x-3)=  (2x-1)(x-3)

x²-9=(x-3)(x+3)

(2x-1)(x-3)/(x-3)(x+3)=  (2x-1)/(x+3)