Question

Suma a 3 nr. rationale este 63,56.Sa se afle nr. stiind ca al doilea este jumatate din primul si de doua ori mai mare decat al treilea.

Answer 1

$x+y+z=63,56 \\ y= \frac{x}{2} ;x=2y\\ y=2z ;z= \frac{y}{2} \\ 2y+y+\frac{y}{2}= 63,56 \\ 7y=127,12 \\ y=18,16 \\ x=2y=2*18,16=36,32 \\ z= \frac{y}{2} =\frac{18,16}{2} =9,08 \\ Verificare:x+y+z=36,32+18,16+9,08=63,56$

Answer 2

a+b+c= 63,56
b = a/2 => a = 2b
b = 2c => a = 2*2c = 4c

4c + 2c + c = 63,56
7c = 63,56
c = 63,56/7
c = 9,08
a = 4*9,8
a = 36,32
b = 2*9,8
b = 18,16