Question

suma a 4 nr naturale consecutive este 114

Answer 1

Presupun ca trebuie sa aflii numerele...

a+a+1+a+2+a+3=114
4a+6=114
4a=114-6
4a=108
a=108:4
a=27

Deci primul numar este 27, al doilea 28, al treilea 29 si ultimul 30...


Succes! ^-^

Answer 2

a+ b + c + d = 114

|___| a

|___|..+1..| b

|___|..+1..|..+1..| c

|___|..+1..|..+1..|..+1..| d

114 - (1+1+1+1+1+1)=114 - 6= 108

1+1+1+1=4 (segmente egale)

108:4=27 (valoarea unui segment)

a=1×27=27

b=1×27+1=27+1=28

c=1×27+1+1=27+1+1=29

d=1×27+1+1+1=27+1+1+1=30

verificare:
27+28+29+30=114