Question

suma    a patru numere naturale consecutive este58.aflati numerele.
                                                       

Answer 1

a+(a+1)+(a+2)+(a+3)=58
4a+6=58
4a=58-6
4a=52
a=52:4
a=13⇒a+1=14⇒a+2=15⇒a+3=16

Numerele sunt: 13,14,15 si 16

Answer 2

a+(a+1)+(a+2)+(a+3)=58
4a+6=58
4a=58-6=>4a=52
a=52/4
a=13
numerele sunt:13,14,15,16