Question

Tema la matematica. doar cele încercuite dau coroana. va rog frumos rapid
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Answer 1

Răspuns:

Explicație pas cu pas:

1)

c)

(1/9)³=1³/9³= 1/729

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d)

(23/99)²=23²/99²=529/9.801

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e)

2¹/₄= (2*4+1)/4= 9/4

(9/4)³=9³/4³=729/64

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2)

c)

[(2/13)³]⁶= (2/13)³ˣ⁶=(2/3)¹⁸=2¹⁸/3¹⁸

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3)

d)

5⁴/₉=(5*9+4)/9= 49/9)

(49/9)¹⁸:(49/9)¹⁷

= (49/9)¹⁸⁻¹⁷

= (49/9)¹

= 49/9

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e)

1¹/₂=(1*2+1)/2=3/2

(3/2)¹⁵:(3/2)¹¹

=(3/2)¹⁵⁻¹¹

= (3/2)⁴

= 3⁴/2⁴

= 81/16

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f)

4⁴/₁₅=(4*15+4)/15=64/15

(64/15)²³:(64/15)²²

=(64/15)²³⁻²²

= (64/15)¹

= 64/15