Question

Testul 1 va rog urgent, coronita si puncte.

Answer 1

1) a) $2x+1=-5$
[tex]2x=-5-1 [/tex]
$2x=-6$
x= -3

b) $0,5x-1,3=2,7$
$0,5x=2,7+1,3$
$0,5x=4$
x=8

c) $\sqrt{3} x=2 \sqrt{6}$
împarte totul cu $\sqrt{3}$
$x= 2 \sqrt{2}$

2) 2(x+1)-3(2-x)=x+3(2x+1)
2x+2-6+3x=x+6x+3
5x-4=7x+3
5x-7x=3+4
-2x=7
$x= -\frac{7}{2}$

4) $(x+1)^{2} +2(x-2)(x+2)=(3x-1)(x-3)+2$
$x^{2} +2x+1+2( x^{2} -4)=3 x^{2} -9x-x+3+2$
$x^{2} +2x+1+2 x^{2} -8=3 x^{2} -10x+5$
$3 x^{2} +2x-7=3 x^{2} -10x+5$
$2x-7=-10x+5$
$2x+10x=5+7$$12x=12$
$x=1$


5) $-2x+3(x-3)+ \frac{x-1}{2} = \frac{x+1}{3} - \frac{x+3}{6}$
$-2x+3x-9+ \frac{x-1}{2} = \frac{x+1}{3} - \frac{x+3}{6}$
$x-9+ \frac{x-1}{2} = \frac{x+1}{3} - \frac{x+3}{6}$
$6x+54+3(x-1)=2(x+1)-(x+3)$
$6x-54+3x=2x+2-x$
9x-54=x+2
9x-x=2+54
8x=56
x=7
acum înlocuiești pe x în $mx-3+2x=2(m-x)+5$
$7m-3+2*7=2(m-7)+5$
$7m-3+14=2m-14+5$
$7m+11=2m-9$
$7m-2m=-9-11$
$5m=-20$
$m=-4$