Question

$2^{-1}+ 4^{-2}$

Answer 1

   
[tex]\displaystyle\\ 2^{-1}+ 4^{-2} = \\\\ = \frac{1}{2^1} + \frac{1}{4^2} =\\\\=\frac{1}{2} + \frac{1}{16} =\\\\ = \frac{1\times 8}{2\times 8} + \frac{1}{16} =\\\\ = \frac{8}{16} + \frac{1}{16} =\frac{8+1}{16} = \boxed{\frac{9}{16}} =\boxed{\frac{3^2}{2^4}} [/tex]

Answer 2

1/2+1/4²=8/16+1/16=9/16
as simple as that!!!