Question

$\frac{x-1}{2} + \frac{2x+1}{3} =1- \frac{2x+1}{6}$

Answer 1

Amplificam prima fractie cu 3, a 2-a cu 2: $\frac{3x-3}{6} + \frac{4x+2}{6}= \frac{6}{6} - \frac{2x+1}{6}$⇒$3x-3+4x+2=6-2x-1$⇒$7x-1=6-2x-1$ (trecem 1 in cealalta parte) => 7x=6-2x => 9x=6, x=$\frac{6}{9} = \frac{2}{3}$. Deci, $x= \frac{2}{3}$.