Question

$log_{3}(2x + 4) = 1$
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Answer 1

 

$\displaystyle\\\log_3(2x+4)=1\\\\2x+4=3^1\\\\2x+4=3\\\\2x=3-4\\\\2x=-1\\\\\boxed{x=-\frac{1}{2}}$

$\displaystyle\\\text{Verificare:}\\\\x=-\frac{1}{2}\\\\\log_3\left(2\cdot\left(-\frac{1}{2}\right)+4\right)=\\\\=\log_3\left(-\frac{2}{2}+4\right)=\log_3(-1+4)\log_3(3)=1~~~(\text{Corect})$