Question

$tg^{2} 60 + ctg^{2} 135 - \frac{sin 135}{cos 45} = ?$
Va rog, scrieti etapele de rezolvare rand pe rand. Multumesc anticipat!

Answer 1

Rezolvarea rand pe rand in poza atasata... Pe ultimul rand, la calculul final e 3+1-1=3. Era noapte cand am rezolvat ... :)) Scuze!

Answer 2

[tex]\it E = tg^260^o+ctg^2135^o-\dfrac{sin135^o}{cos45^o} \\ \\ \\ tg^2 60^o = (\sqrt3)^2 =3 \\ \\ \\ ctg^2 135^o=ctg^245^o=1 \\ \\ \\ \dfrac{sin135^o}{cos45^0} = \dfrac{sin45^o}{cos45^o} = tg45^o=1[/tex]

$\it E = 3+1-1=3$