Question

Transforma in Sl:
1,6 nC ,
350 mA,
0,5 k lianta,
20 kW·h

Answer 1

1,6 nC=1,6x10⁻⁹C
350mA=0,35A
20kWh=20*1000*3600=72*10⁶J
0,5k=500

Answer 2

1,6 nC = 1,6·10⁻⁹ C
350 mA = 0,35 A
0,5 k       = 500 (nu stiu ce!)
20 kW·h = 20000x 3600 = 72·10⁶ J