Question

Trapezul ABCD cu ABIIDC are AD=DC,m(DCA)=α si m(ACB)=β.Aflati masurile unghiurilor trapezului.                           

Answer 1

$m\left(\widehat{C}\right)=\alpha+\beta$
$m(\widehat{B}=180^{\circ}-m(\widehat{C})=180^{\circ}-\alpha-\beta$
Triunghiul ADC este isoscel, deci $m(\widehat{DAC})=\alpha$
Atunci $m(\widehat{D})=180^{\circ}-2\alpha$
$m(\widehat{A})=180^{\circ}-m(\widehat{D})=2\alpha$