Question

Triunghiul ABC~triunghiulDEF ab=18 de=12 df=10 ef=16 aflati lungimile segmentelor [AC] si[BC]

Answer 1

$\frac{AB}{DF}$=$\frac{AC}{DE}$⇒ AC=$\frac{ABXDE}{DF}$=$\frac{18X12}{10}$=21,6
$\frac{AB}{DF}$=$\frac{BC}{FE}$⇒BC=$\frac{ABXFE}{DF}$=$\frac{18X16}{10}$=28,8
Sper sa fie corect:) .

Answer 2

tr ABC asemenea cu tr DEF -> AB/DE=AC/DF=BC/EF echivalent cu 18/12=AC/10=BC/EF
luam primul raport 18/12=AC/10 -> AC=18*10 supra 12=15 AC=15
luam al 2lea raport18/12=BC/EF adica 3/2=BC/EF-> BC=3 si EF=2