Question

Un corp cu masa de 27 g este suspendat de un resort avand constanta elastica k 100 N / m . Care este alungirea resortului ? ( g = 10 N / kg )

Answer 1

$m=27 \ g=0,027 \ kg \\ k=100 \ N/m \\ g=10 \ N/kg \\ \boxed{\Delta l-?} \\ \bold{Rezolvare:} \\ \boxed{k=\frac{F_e}{\Delta l}} \ \ \Rightarrow \Delta l= \frac{F_e}{k} \\ F_e=G=m \cdot g \\ F_e=G=0,027 \ kg \cdot 10 \ N/kg \\ F_e=0,27 \ N \\ \Delta l= \frac{0,27 \ N}{100 \ N/m} \\ \Rightarrow \boxed{\Delta l=0,002 \ 7 \ m}$