Question

URGENT!!!!!!!!!!!!!!!!!!!!!!!!!! DAU COROANA!!!!!!!!!!!!
ce masade carbura de calciu, cu partea demasa a impuritatii 20% este necesara pentru a obtine acetilena, suficienta dea obtine benzen cu volumul de 2l si densitatea 0,88g/cm^3?

Answer 1

ro=m/V => m=0,88*2000 = 1760g C6H6

64g........................26g
CaC₂ + 2H₂O ⇒ C₂H₂ + Ca(OH)₂
xg..........................1760g

x=64*1760/26 = 4332,3g CaC2

4332,3g CaC2...........................80%
xg..............................................100%

x=5415,375g

3*26g.........78g
3C₂H₂ ⇒ C6H6
xg...............1760g

x=1760g