Question

URGENT!!!! EXERCIȚIUL 6

Answer 1

Răspuns:

Explicație pas cu pas:

$a = \frac{4}{3}-\frac{4}{3} *[\frac{4}{3} -(0,(3))^2]:4\frac{8}{9} =$

$= \frac{4}{3}-\frac{4}{3} *[\frac{4}{3} -(\frac{3}{9} )^2]:\frac{4*9 + 8}{9} =$

$= \frac{4}{3}-\frac{4}{3} *[\frac{4}{3} -(\frac{1}{3} )^2]:\frac{36 + 8}{9} =$

$= \frac{4}{3}-\frac{4}{3} *(\frac{4}{3} -\frac{1}{3^2}):\frac{44}{9} =$

$= \frac{4}{3}-\frac{4}{3} *(\frac{4*3}{3*3} -\frac{1}{9})*\frac{9}{44} =$

$= \frac{4}{3}-\frac{4}{3} *(\frac{12}{9} -\frac{1}{9})*\frac{9}{44} =$

$= \frac{4}{3}-\frac{4}{3} *\frac{12-1}{9}*\frac{9}{44} =$

$= \frac{4}{3}-\frac{4}{3} *\frac{11}{9}*\frac{9}{44} =$

$= \frac{4}{3}-\frac{4}{3} *\frac{11}{9}*\frac{9}{4*11} =$

$= \frac{4}{3}-\frac{1}{3} =$

$= \frac{4-1}{3} =$

$= \frac{3}{3} =$

$= 1$ ∈ N

Answer 2

$\it(0,(3))^2=\Big(\dfrac{3}{9}\Big)^2=\dfrac{\ 9^{(9}}{81}=\dfrac{1}{9}$

$\it n=\dfrac{4}{3}-\dfrac{4}{3}\cdot\Big(\dfrac{^{3)}4}{\ 3}-\dfrac{1}{9}\Big):\dfrac{44}{9}=\dfrac{4}{3}-\dfrac{4}{3}\cdot\dfrac{11}{9}\cdot\dfrac{9}{44}=\dfrac{4}{3}-\dfrac{1}{3}=\dfrac{3}{3}=1\in\mathbb{N}$