Question

va rog aflati termenul necunoscut: 1+(6:3-a:8):2=2

Answer 1

1+(2-a:8):2=2
(2-a:8):2=2-1=1
2-a:8=1x2=2
a:8=2-2=0
a:8=0
a=0x8=0

Answer 2

1+[6/3-a/8]/2=2
⇒[6/3-a/8]/2=2-1
⇒[6/3-a/8]/2=1
⇒[6/3-a/8]=1·2
⇒[6/3-a/8]=2
⇒[2-a/8]=2
⇒2-a/8=2
⇒a/8=2-2
⇒a/8=0
⇒a-0·8
⇒a=0;
VERIFICARE 1+[6/3-0/8]/2=1+[2-0]/2=1+2/2=1+1=2;