Question

Vă rog ajutați-mă!!!!!​

Answer 1

$\displaystyle a)~x=\Bigg(\frac{6}{\sqrt{63} } -\frac{4}{\sqrt{112} } +\frac{6}{\sqrt{28} }\Bigg) \cdot \Bigg(\frac{2}{\sqrt{7} } \Bigg)^{-1}=\Bigg(\frac{^{4)}6}{3\sqrt{7} } -\frac{^{3)}4}{4\sqrt{7} }+\frac{^{6)}6}{2\sqrt{7} }\Bigg) \cdot \frac{\sqrt{7} }{2} = \\\\ =\frac{4 \cdot 6-3 \cdot 4+6 \cdot 6}{12\sqrt{7} } \cdot \frac{\sqrt{7} }{2} =\frac{24-12+36}{12} \cdot \frac{1}{2} =\frac{48}{12} \cdot \frac{1}{2} =\frac{48}{24} =2$

$\displaystyle b)~y=2^{3^3}\cdot 4^3:8^{10}=2^{27}\cdot 2^{2 \cdot 3}:2^{3\cdot 10}=2^{27}\cdot 2^6 :2^{30}=2^{27+6-30}=2^3=8$

$x=2;~y=8\\\\ m_g=\sqrt{x \cdot y} =\sqrt{2 \cdot 8} =\sqrt{16} =4=2^2$