Question

va rog ajutor dau coroana​

Answer 1

$\bf a)\\ \\ \it \mathcal{A}=\dfrac{AB\cdot AC \cdot sinA}{2}=\dfrac{12\cdot8\cdot sin30^o}{2}=6\cdot8\cdot\dfrac{1}{2}=\dfrac{48}{2}=24\ cm^2\\ \\ \bf b)\\ \\ \it \mathcal{A}=\dfrac{AC\cdot BC \cdot sinC}{2}=\dfrac{6\sqrt2\cdot6\cdot sin45^o}{2}=3\cdot \not\sqrt2\cdot6\cdot\dfrac{\not\sqrt2}{\not2}=3\cdot6=18\ cm^2$