Question

va rog dau coroana!!!​

Answer 1

a)

$(1+i)*\frac{1}{1-i}$

$\frac{1+i}{1-i}$

$=i$

b)

$-6i*\frac{1}{1+3i}$

$-\frac{6i}{1+3i}$

$=- \frac{9}{5} - \frac{3}{5} i$

c)

$\frac{1-\sqrt{3}i }{1+\sqrt{3}i }$

$=-\frac{1}{2} -\frac{\sqrt{3} }{2} i$

d)

$\frac{(\sqrt{3}+\sqrt{2}i)*(\sqrt{3}+\sqrt{2}i }{5}$

$\frac{(\sqrt{3}+\sqrt{2}i)^{2} }{5}$

$\frac{3+2\sqrt{6}i+2i^{2} }{5}$

$\frac{3+2\sqrt{6}i-2 }{5}$

$=\frac{1}{5} +\frac{2\sqrt{6} }{5} i$