va rog dau corona repede:(((
Răspunsuri la întrebare
Reguli pentru astfel de calcule:
a^m x a^n = a^ m+n
a^m : a^n = a^m-n
(a^n)^m = a^m x n
a^b x c^b = (a x c)^b
bRaspunsurile:
a)5^18 x 5^22= 5^40
b) 6^6 x 6^9 = 6^15
c) 7^9 x 49 = 7^9 x 7^2 = 7^11
d) 17^72 : 17^25 = 17^47
e) 10^16 : 10^16 = 1
f) 125 : 5^2 = 5^3 : 5^2 = 5^1
g) 2^25 x 2 : 2^13 = 2^25 x 2^1 : 2^13 = 2^26 : 2^13 = 2^13
h) (21^7)^3 = 21^21
i) [(2^2)^3]^4 = [2^6]^4 = 2^24
j) (3^17 x 3^3)^2 : ( 3^5 x 3^3) = (3^20)^2 : 3^8=3^40 : 3^8 = 3^32
k) 21^56 x 2^56 : 42^16 = (21 x 2)^56 : 42^16 = 42^56 : 42^16 = 42^40
l) 18^123 : 2^123 x (3^2-1)^123= 18^123 : 2^123 x (9-1)^123 = 18^123 : 2^123 x 8^123 = (18 : 2)^123 x 8^123 = 9^123 x 8^123 = (9 x 8)^123 = 72^123
m) (14^4)^4 : 2^16 x (3+1)^16 = 14^16 : 2^16 x 4^16= (14 : 2 )^16 x 4^16 = 7^16 x 4^16 = (7 x 4)^16 = 28^16
n) (2^4)^4 : 2^2^4 x (3^2-1) - 2005^0 x 2^2 = 2^16 : 2^2^4 x (9-1)- 2005^0 x 2^2 = 2^16 : 2^2^4 x 8 - 2005^0 x 2^2 = 2^16 : 2^16 x 8 - 1 x 4 = 1 x 8 - 1 x 4 = 8 - 4 = 4 sau 2^2
Sper ca te-am ajutat !