Question

Vă rog! Exercitiul din imagine!

Answer 1

[$\frac{5}{6}$-10$\frac{2}{7}$×($\frac{5}{24}$ *amplificat cu 9*-$\frac{7}{54}$ *amplificat cu 4*-$\frac{11}{36}$ *amplificat cu 6*)×(-2$\frac{2}{3}$)+3]÷0,0(1)=

=[$\frac{5}{6}$-$\frac{72}{7}$×($\frac{45}{216}$-$\frac{28}{216}$-$\frac{66}{216}$)×(-$\frac{8}{3}$+$\frac{3}{1}$]÷$\frac{1}{90}$

=[$\frac{5}{6}$-$\frac{72}{7}$×(-$\frac{49}{216}$)×(-$\frac{8}{3}$+$\frac{3}{1}$]÷$\frac{1}{90}$

=($\frac{5}{6}$-$\frac{72}{7}$×$\frac{392}{648}$ *aceste doua fractii au fost simplificate ramanand cu $\frac{1}{1}$×$\frac{56}{9}$*+$\frac{3}{1}$)÷$\frac{1}{90}$

=($\frac{5}{6}$ *amplificat cu 3*-$\frac{56}{9}$ *amplificat cu 2*+$\frac{3}{1}$ *amplificat cu 18*)÷$\frac{1}{90}$

=($\frac{15}{18}$-$\frac{112}{18}$+$\frac{54}{18}$)×$\frac{90}{1}$

=(-$\frac{43}{18}$)×$\frac{90}{1}$ *se simplifica 18 cu 90 si raman 1 si 5*

=-215